Example of a ring satisfying this variant definition of "symmetric" on
nilpotent elements
I want an example to show that if $a,b$ are nilpotent elements of a ring
$R$ with 1 and if $c$ is any element of $R$, then $abc=0\Rightarrow acb=0$
but $cab=0$ does not imply $acb=0$.
This is unlike symmetric ring, where we know that if $a,b,c\in R$ and
$abc=0$ implies that $acb=0$.
Please help me to find a ring where to search for an example or help me to
show that if $abc=0 \Rightarrow acb=0$, then $cab=0 \Rightarrow acb=0$ for
above mentioned $a,b,c$.
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